x^2+2x+40=0

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Solution for x^2+2x+40=0 equation:


Simplifying
x2 + 2x + 40 = 0

Reorder the terms:
40 + 2x + x2 = 0

Solving
40 + 2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + 2x + -40 + x2 = 0 + -40

Reorder the terms:
40 + -40 + 2x + x2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + 2x + x2 = 0 + -40
2x + x2 = 0 + -40

Combine like terms: 0 + -40 = -40
2x + x2 = -40

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -40 + 1

Reorder the terms:
1 + 2x + x2 = -40 + 1

Combine like terms: -40 + 1 = -39
1 + 2x + x2 = -39

Factor a perfect square on the left side:
(x + 1)(x + 1) = -39

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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